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7n^2+7n-15=0
a = 7; b = 7; c = -15;
Δ = b2-4ac
Δ = 72-4·7·(-15)
Δ = 469
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{469}}{2*7}=\frac{-7-\sqrt{469}}{14} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{469}}{2*7}=\frac{-7+\sqrt{469}}{14} $
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